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Java Arrays
Java Arrays
Initialise

Fixed contents n/a int a[]={1,2,3,4,5};
1 2 3 4 5
Repeat value 'e' 'n' times e=3;
n=5;
int a[]=new int[5];
Arrays.fill(a,e);
3 3 3 3 3

Insert

Prepend element 'e' int a[]={2,3,4};
e=1;
a=Arrays .copyOf(a ,a .length +1) ;
System .arraycopy(a ,0,a,1,a.length-1);
a[0]=e;
1 2 3 4
Append element 'e' int a[]={1,2,3};
e=4;
a=Arrays .copyOf(a,a.length+1);
a[a.length-1]=e;
1 2 3 4
Insert element 'e' at index 'n' int a[]={1,2,3,4,5};
e=666;
n=3;
a=Arrays .copyOf(a ,a .length +1) ;
System .arraycopy(a ,n,a,n+1,a.length-n-1);
a[n]=e;
1 2 3 666 4 5
Prepend array 'b' int a[]={1,2,3,4,5};
int b[]={10,20,30};
a=Arrays .copyOf(a ,a .length +b .length) ;
System .arraycopy(a ,0 ,a ,b .length ,a .length-b .length) ;
System .arraycopy(b ,0,a,0,b.length);
10 20 30 1 2 3 4 5
Append array 'b' int a[]={1,2,3,4,5};
int b[]={10,20,30};
a=Arrays .copyOf(a ,a .length +b .length) ;
System .arraycopy(b ,0 ,a ,a .length-b .length,b.length);
1 2 3 4 5 10 20 30
Insert array 'b' at index 'n' int a[]={1,2,3,4,5};
int b[]={10,20,30};
n=3;
a=Arrays .copyOf(a ,a .length +b .length) ;
System .arraycopy(a ,n ,a ,n +b .length ,a .length-n-b .length) ;
System .arraycopy(b ,0,a,n,b.length);
1 2 3 10 20 30 4 5
Concatenate array 'a' and array 'b' int a[]={1,2,3};
int b[]={4,5,6};
int c[]=new int[a.length+b.length];
System .arraycopy(a ,0 ,c ,0 ,a .length) ;
System .arraycopy(b ,0,c,a.length,b.length);
1 2 3 4 5 6
Insert element 'e' at indices in 'b' int a[]={1,2,3,4,5};
int b[]={0,2,4};
e=666;
for (n=b .length-1 ;n>=0 ;--n)
{ a=Arrays .copyOf(a ,a .length +1) ;
System .arraycopy(a ,b[n] ,a ,b[n]+1,a.length-b[n]-1); a[b[n]]=e; }
666 1 2 666 3 4 666 5

Overwrite

Overwrite first element int a[]={1,2,3};
a[0]=666;
666 2 3
Overwrite last element int a[]={1,2,3};
a[a.length-1]=666;
1 2 666
Overwrite element at index 'n' int a[]={1,2,3};
n=1;
a[n]=666;
1 666 3
Overwrite elements from index 'n' (inclusive) int a[]={1,2,3,4,5,6};
int b[]={7,8,9};
n=2;
System .arraycopy(b ,0,a,n,b.length);
1 2 7 8 9 6

Count

Length of array int a[]={1,2,3};
n=a.length;
3

Retrieve by index

Retrieve first element int a[]={1,2,3};
e=a[0];
1
Retrieve last element int a[]={1,2,3};
e=a[a.length-1];
3
Retrieve element 'n' int a[]={1,2,3};
n=2;
e=a[n];
3
Retrieve out-of-bounds element 'n' int a[]={1,2,3};
n=4;
String err="in bounds";
try { e=a[n] ; }
catch ( ArrayIndexOutOfBoundsException ex ) { err="out of bounds" ; }
out of bounds

Slice

Slice from index 'm' to 'n' (inclusive) int a[]={1,2,3,4,5};
m=1;
n=3;
a=Arrays .copyOfRange(a,m,n+1);
2 3 4
Slice from index 'n' onwards (inclusive) int a[]={1,2,3,4,5};
n=2;
a=Arrays .copyOfRange(a ,n,a.length);
3 4 5
Slice up to index 'n' (inclusive) int a[]={1,2,3,4,5};
n=3;
a=Arrays .copyOfRange(a,0,n+1);
1 2 3 4

Search

Find index of element 'e' (forward) int a[]={1,2,3,4,5};
e=3;
Arrays .sort(a) ;
n=Arrays .binarySearch(a,e);
2

Sort

Sort in ascending order int a[]={5,1,4,3,2};
Arrays.sort(a);
1 2 3 4 5
Sort index range 'm' to 'n' (inclusive) int a[]={5,1,4,3,2};
m=1;
n=3;
Arrays.sort(a,m,n+1);
5 1 3 4 2

Compare

Test for equality (true) int a[]={1,2,3,4,5};
int b[]={1,2,3,4,5};
t=Arrays.equals(a,b);
1
Test for equality (false) int a[]={1,2,3,4,5};
int b[]={1,20,3,4,5};
t=Arrays.equals(a,b);
0

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14-11-09@15:37:24